# Line slope calculator x-4y=-12

**Straight line given by points A[0; 3] and B[4; 4]**

## Calculation:

**Slope-intercept form of line:**y = 0.25x+3

**Canonical form of the line equation:**x-4y+12 = 0

**Parametric form of the line equation:**

x = 4t

y = t+3 ; t ∈ R

**Slope:**m = 0.25

**Slope angle of line: φ =**14°2'10″ = 0.245 rad

**X intercept:**x

_{0}= -12

**Y intercept:**y

_{0}= q = 3

**Distance line from the origin:**d

_{0}= 2.9104

**The length of the segment AB: |AB| =**4.1231

**Vector: AB =**(4; 1)

**Normal vector: n =**(1; -4)

**Midpoint of the segment AB: M =**[2; 3.5]

**Perpendicular Bisector equation:**4x+y-11.5 = 0

**Vector OA = (0; 3) ; |OA| = 3**

**Vector OB = (4; 4) ; |OB| = 5.6569**

**Scalar product OA .OB = 12**

**Angle ∠ AOB = 45° = 0.7854 rad**